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Cum se rezolva problema in continuare? :) please

Cum Se Rezolva Problema In Continuare Please class=

Răspuns :

C: 6  :12 = 0,5
H : 1 : 1 = 1
      n compus = 1,27/127 = 0,01 moli   nCl = 0,71/35,5 = 0,02 atomi
⇒                                             1mol......................................2 atomi
formula : CxH2xCl2      14x + 71 = 127   14x = 56      x = 4
⇒ C4H8Cl2
b) Cl-CH=CH-CH2-CH3     CH2= C(Cl)-CH2-CH3