ms = 300g sol. HCl
C = 36,5%
Zn + 2HCl => ZnCl2 + H2
C = md/ms*100 => md = C*ms/100 = 36,5*300/100 = 109,5g HCl
MHCl = 36,5g/mol
n = m/M = 109,5/36,5 = 3 moli HCl
a) 1 mol Zn...............2 moli HCl
x moli Zn...................3 moli HCl
x = 1,5 moli Zn
b) 2 moli HCl....................136g ZnCl2
3 moli HCl..........................xg ZnCl2
x = 204g ZnCl2
c) n Zn = n H2 = 1,5 moli
n = V/Vm => V =n*Vm = 1,5*22,4 = 33,6 L H2