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[1-(1 SUPRA3) LA PUTEREA2×1, (4)]-1SUPRA3+5SUPRA2

Răspuns :

[1-(1/3)²×1, (4)]-1/3+5/2=
=
[1-1/9×13/9]-2/6+15/6=
= [1-13/81]+13/6=
= (81-13)/81+13/6=
= 68/81+13/6=
=
(136+351)/162=487/162