[tex]1) \frac{2}{5}\cdot \frac{4}{3}= \frac{2\cdot4}{5\cdot3} = \frac{8}{15} \\ \\ 2) \frac{12}{25}\cdot \frac{20}{27}= \frac{4\cdot4}{5\cdot9} = \frac{16}{45} \\ \\ 3) \frac{2}{3}\cdot \frac{6}{5}- \frac{5}{100}= \frac{4}{5}- \frac{5}{100}= \frac{80-5}{100}= \frac{75}{100}= \frac{15}{20} \\ \\4) \frac{5}{4}\cdot \frac{9}{4\cdot5}- \frac{1}{4\cdot4}= \frac{45-5}{80}= \frac{40}{80}= \frac{1}{2}[/tex]
[tex]5) \frac{3}{7}- \frac{3}{69}= \frac{3\cdot23\cdot3-3\cdot7}{3\cdot23\cdot7}= \frac{207-21}{483}= \frac{186}{483}[/tex]
[tex]6) (3,7-3,69)\cdot[1+0,(01 )- \frac{1}{99}= ; 0,(01)= \frac{1}{99} \\ \\ 0,01\cdot[1+ \frac{1}{99}- \frac{1}{99}]= 0,01[/tex]
[tex]7) 1\frac{1}{6}= \frac{7}{6};9 \frac{1}{4}= \frac{37}{4} [/tex]
[tex]0,15= \frac{15}{100}= \frac{3}{20} ; 0,2\cdot0,15=0,03[/tex]
[tex](\frac{7}{6}\cdot \frac{37}{4})( \frac{3}{20}+ \frac{3}{100})+ \frac{17}{16}= [/tex]
[tex] \frac{259}{24}\cdot \frac{18}{100}+ \frac{17}{16} = [/tex]
