Răspuns: 1880
Explicație pas cu pas:
Salut!
[tex]\bf 10^{3}:5^{2}+10\cdot\{2^{10}:64+2^{3}\cdot[1035:(5\cdot3^{2})-(2^{37}\cdot7^{37})^{2}:(4^{36}\cdot 49^{37}):2]\} =[/tex]
[tex]\bf 1000:25+10\cdot\{2^{10-6}+2^{3}\cdot[1035:45-(2^{74}\cdot7^{74}):(2^{2\cdot36}\cdot 7^{2\cdot37}):2]\} =[/tex]
[tex]\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{74}\cdot7^{74}):(2^{72}\cdot 7^{74}):2]\}=[/tex]
[tex]\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{74-72}\cdot7^{74-74}):2]\} =[/tex]
[tex]\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{2}\cdot7^{0}):2]\} =[/tex]
[tex]\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{2}\cdot 1):2]\} =[/tex]
[tex]\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2^{2}:2)] =[/tex]
[tex]\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2^{2-1})] =[/tex]
[tex]\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2)] =[/tex]
[tex]\bf 40+10\cdot(2^{4}+2^{3}\cdot 21) =[/tex]
[tex]\bf 40+10\cdot(16+8\cdot 21) =[/tex]
[tex]\bf 40+10\cdot(16+168) =[/tex]
[tex]\bf 40+10\cdot 184 =[/tex]
[tex]\bf 40 + 1840=[/tex]
[tex]\boxed{\bf 1880}[/tex]
Succes la scoala!
