Ecuația reacției chimice:
_0.5moli_ _x=0.5 moli_
2Mg + O₂ ------> 2MgO
2 moli 2 moli
Rezolvare:
[tex]n_{Mg}=\frac{m}{M}=\frac{12 \ (g)}{24\ (g/mol)}=0.5 \ moli[/tex]
[tex]M_{MgO}=24+16=30\ g/mol[/tex]
[tex]n_{MgO}=x=0.5\ moli[/tex]
[tex]m_{MgO}=n*M=0.5\ (moli)*30\ (g/mol)=15\ g[/tex]