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B=ab+5ba-126=pp
10a+b+500+10b+a-126=
=11a+11b+374=
=11*(a+b+34) deoarece a+b+34>11
=11*11*k^2=(11*k)^2 , unde (a+b+34)=11*k^2
1≤a≤9
1≤b≤9 ⇒2≤a+b≤18 ⇒2+34≤a+b+34≤18+34 ⇒36≤a+b+34≤52 ⇒36≤11*k^2≤52 rezulta k^2=4 deci k=2
a+b+34=11*4=44 rezulta a+b=44-34=10
a=1 b=9
a=2 b=8
a=3 b=7
a=4 b=6
a=5 b=5
a=6 b=4
a=7 b=3
a=8 b=2
a=9 b=1
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ab={19,28,37,46,55,64,73,82,91}
verificare
19+591-126=484=22²
28+582-126=484=22²
si asa mai departe deci B=22²
