-calculez masa si mol HCl
c= mdx100/ms---> md=8x36,5gHCl
n=m/M= 8X36,5g/36,5g/mol=8mol HCl
-calculez moli NH3
n=N/N,A= 421,54x10²² molec./6,023x10²³molec/mol= 7mol NH3
N,A este numarul lui Avogadro
-ecuatia reactiei este
1mol.......1mol.........1mol
NH3 + NHCl--- >NH4Cl
7mol.....................x=7mol
rezulta exces de 1 mol HCl
m,sare= 7mol(14gN+4gH+35,5gCl)/mol=......................calculeaza !!!!