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rezolvati ecuatiile: 27(n-27)=27; (21-z)/27=0;44/(c+44)=1:3x+4x-2-5x=0


Răspuns :

1) 27(n-27)=27⇔n-27=27/27⇔n-27=1⇔n=27+1=28
2) (21-z)/27=0⇔21-z=0/27⇔21-z=0⇔z=21-0=21
3) 44/(c+44)=1⇔c+44=44/1⇔c+44=44⇔c=44-44=0
4) 3x+4x-2-5x=0⇔7x -2-5x=0⇔7x-5x-2=0⇔2x-2=0⇔2x=0+2⇔2x=2⇔x=2/2=1