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400 g de solutie NaOH cu c1=30 %reactioneazacu osolutie de HCl de c2=50%
a)Ce masa de solutie de HCl s-a consumat?
b)Calculati masa produsilor de reactie


Răspuns :

a) NaOH + HCl = NaCl + H2O
c = md*100/ms
md = 400*30/100 = 120 g NaOH
M NaOH = 40 g/mol
M HCl = 36,5 g/mol
M NaCl = 58,5 g/mol
M H2O = 18 g/mol
40 g NaOH.......36,5 g HCl.....58,5 g NaCl.....18 g H2O
120 g NaOH...........x......................y.....................z
x = 109,5 g HCl
c = md*100/ms
ms = 109,5/50*100 = 219 g soluție HCl 50%
b) y = 175,5 g NaCl
z = 54 g H2O