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Determinati numerele naturale, stiind
ca:a+b=90;b+c=110;a+c=100.


Răspuns :

Aflam suma celor 3 numere,adunand cele 3 relatii:
a+b+b+c+a+c = 90+110+100
2×a+2×b+2×c = 300
2×(a+b+c) = 300
a+b+c = 300:2 = 150
c = 150 - 90 = 60
a = 150 - 110 = 40
b = 150 - 100 = 50