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Metoda mersului invers: (3•a+5)•5-3=292. (c-17)•3+15=45

Răspuns :

1.(3*a+5)*5-3=292/+3
(3*a+5)*5=295/:5
3*a+5=59/-5
3*a=54/:3
a=18

2.(c-17)*3+15=45/-15
(c-17)*3=30/:3
c-17=10/-17
c= -7