[tex] \lim_{x \to \infty} ( \sqrt{x^2+1}-x) [/tex]
Amplificam cu conjugata , adica cu [tex] \sqrt{x^2+1}+x [/tex]
Obtinem :[tex] \lim_{x \to \infty} \frac{ ( \sqrt{x^2+1}-x)( \sqrt{x^2+1}+x) }{ \sqrt{x^2+1}+x }= \lim_{x \to \infty} \frac{x^2+1-x^2}{ \sqrt{x^2+1}+x } = \frac{1}{ \sqrt{x^2+1}+x } =0[/tex]
