1s2 2s2 2p4 - oxigenul
=> XO
%O = mO/mXO * 100
7,175 = 16*100/(16+x)
1600 = 114,8 + 7,175x
x = 207 => A = 207 => Pb => r - PbO - oxid de plumb
M r = 207+16 = 223 g/mol
M r: M x: M y = 223: M x: M y = 1: 1,072: 3,072
M x = 239 => x - PbO2 - dioxid de plumb
M y = 685 => Pb3O4 - miniu de plumb
p - 2PbCO3·Pb(OH)2 - minereu de plumb
2PbCO3*Pb(OH)2 = 3 PbO (r) + 2 CO2 (h) + H2O (i)
