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[tex] \int\ (lnx+1)\ dx = \ ?[/tex]

Va rog mult!!!


Răspuns :

[tex] \int\ {x'(lnx+1)} \, dx =x(lnx+1)- \int\ {x(lnx+1)'} \, dx =xlnx+x-\int\ {1} \[tex]

=xlnx+x-x=xlnx + c