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aflati nr rationale pozitive x,y,z stiind ca sunt invers proportionale cu 0,5 ; 0,6 ; 0,8 si suma lor este 110

Răspuns :

x*0,5=y*0,6=z*0,8=k
x*5=y*6=z*8=10k=K
x=K/5
y=K/6
z=K/8
x+y+z= K(1/5+1/6+1/8)
x+y+z=K(24+20+15)/120

110=K*59/120
K==120*110/59=13200/59

K=13200/59
x=K/5=2640/59
y=K/6=2200/59
z=K/8=1650/59

verificare
x*5=y*6=k*8=13200/59
si 

x+y+z=6490/59=110