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Cat face (×+1)totul la puterea a 2 +(×+1)totul la puterea a2a

Răspuns :

[tex](x+1)^{2}+(x+1)^{2}=2*(x+1)^{2}[/tex]


Sau, daca vrei asa:

[tex](x+1)^{2}+(x+1)^{2}=2*(x+1)^{2}=2(x^{2}+2x+1)=2x^{2}+4x+2[/tex]


Mai explicit putin:
[tex]putem~ scrie~ x+1=a, ~si ~atunci ~(x+1)^{2}=a^{2}, ~iar ~(x+1)^{2}+(x+1)^{2}=a^{2}+a^{2}=a^{2}*1+a^{2}*1=a^{2}(1+1)=a^{2}*2=(x+1)^{2}*2[/tex]
(x+1)^2+(x+1)^2=x^2+2x+2+x^2+2x+2=x^2+4x+4