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2√3 ori 3√2 = ?
√18 - √50 - √128 = ?


Răspuns :


[tex]a)2 \sqrt{3} \times 3 \sqrt{2} = 2 \times 3 \sqrt{3 \times 2} = 2 \times 3 \sqrt{6} = 6 \sqrt{6} \\ \\ b) \sqrt{18} - \sqrt{50} - \sqrt{128} = 3 \sqrt{2} - 5 \sqrt{2} - 8 \sqrt{2} = - 10 \sqrt{2} [/tex]