notam numerele consecutive
a
a+1
a+2
a+3
formulăm ecuatia
a+(a+1)+(a+2)+(a+3)=618
a+a+1+a+2+a+3=618
4a+6=618
4a=618-6
4a=612
a=612:4
a=153
a=153
a+1=153+1=154
a+2=153+2=155
a+3=153+3=156
Verificare 153+154+155+156=618
Numerele consecutive sunt 153, 154, 155, 156
Cel mai mic dintre ele e 153