CH4 + 3 Cl2 = CHCl3 + 3 HCl
randament = n practic/n teoretic * 100
n practic = 1500*66,66/100 = 1000 moli metan
V c.n. = 22,4 l
M CHCl3 = 12+1+35,5*3 = 119,5 g/mol
1 mol metan........3*22,4 l Cl2........119,5 g cloroform
1000 moli metan..........x......................y
x = 67,2 m3 Cl2
y = 119,5 kg cloroform