ma=masa de apă evaporată
c1=50%
ms=800g
c2=40%[tex]c = \frac{md}{ms} \times 100 \\ md = \frac{c \times ms}{100} \\ md= \frac{40 \times 800}{100} = 320g[/tex]
[tex]c1 = \frac{md}{ms1} \times 100 \\ ms1 = \frac{md \times 100}{c1} \\ ms1 = \frac{320 \times 100}{50} = 640g[/tex]
[tex]ma = ms - ms1 \\ ma = 800 - 640 = 160g[/tex]
