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C8H18 + 02 = CO + H20

Octan + Oxigen -> Monoxid de Carbon + Apa

Daca 228g randamente de Octan sunt adaugate, cat Monoxid de Carbon va fi?


Răspuns :


M,octan= 114g/mol;   M,CO=28g/mol

114g.......................................8x28g
m,C8H18   +  17/2O2----->    8CO + 9H2O
228.g..........................................x...............calculeaza !!!!