[tex]a) 0,2+1,(3)= \frac{2}{10}+ \frac{12}{9}= \frac{1}{5}+ \frac{4}{3}= \frac{23}{15}=1,5(3) \\ 1,(3)= \frac{13-1}{9}= \frac{12}{9}= \frac{4}{3}[/tex]
[tex]b)2,5+0,(7)=\frac{5}{2}+\frac{7}{9}= \frac{45+14}{18}= \frac{59}{18}=3,2(7) \\ 0,(7)= \frac{7}{9};2,5= \frac{25}{10}= \frac{5}{2} [/tex]
c)4,25+0,1 (6)
[tex]4,25= \frac{425}{100}= \frac{85}{20}= \frac{17}{4} [/tex]
[tex]0,1(6)= \frac{16-1}{90} = \frac{15}{90}= \frac{1}{6} [/tex]
[tex] \frac{17}{4}+\frac{1}{6}= \frac{102+4}{24} = \frac{106}{24}=4,41(6) [/tex]
d)12,25+0, (36)=
[tex]12,25= \frac{1225}{100}= \frac{49}{4} \\ \\ 0,(36)= \frac{36}{99}= \frac{12}{33}= \frac{4}{11} \\ \frac{49}{4}+ \frac{4}{11}= \frac{11\cdot49+16}{44} = \frac{539+16}{44}= \frac{555}{44}=50,(45) [/tex]
e)1,2 (3)+0,25=
[tex]1,2(3)= \frac{123-12}{90}= \frac{111}{90} [/tex]
[tex]0,25= \frac{25}{100}= \frac{1}{4} [/tex]
[tex] \frac{111}{90}+ \frac{1}{4}= \frac{444+90}{360}= \frac{534}{360}=1,48(3)[/tex]
