[tex]x +y = 210 \\ x - \frac{1}{6} x = y + \frac{1}{6}x[/tex]
Inmultim ecuatia a2a cu 6
[tex]6x + x = 6y + x \\ 5x = 6y + x \\ 4x = 6y \\ x = \frac{3}{2} y[/tex]
Inlocuim in suma initiala
[tex] \frac{3}{2}y + y = 210 \\ 3y + 2y = 420 \\ 5y = 420 \\ y = 84 \\ x = 210 - 84 \\ x = 126[/tex]
Raspuns final:
Andrei are 126 lei
Bogdan are 84 lei