4. b) [tex]( \frac{1}{3}+ \frac{1}{3}*7)*(35.6:356)=( \frac{1}{3}+ \frac{7}{3})*0.1= \frac{8}{3}* \frac{1}{10}= \frac{4}{3}* \frac{1}{5}= \frac{4*1}{3*5}= \frac{4}{15} [/tex]
f) [0.4*3.3-1]:0.5+0.1=[1.32-1]:0.5+0.1=0.32:0.5+0.1=0.64+0.1=0.74
h) [1.6+0.25]:1.916=[tex]1.85: \frac{479}{250} = \frac{32}{20}* \frac{250}{479}= \frac{37}{2}* \frac{25}{479}= \frac{37*25}{2*479}= \frac{925}{958} [/tex]
