2)
4·20+5·12-5 80+60-5
7/3·4/7+9/5·1/3-1/12=4/3+3/5-12=______________ = _________
cmmmc(3,5,12)=2²·3·5=60 60 60
135 ⁽⁵ 27⁽³ 9
= _______ = _____ = _____ = 1 intreg si 1/4
60 12 4
3) deimpartitul=3 intregi si 14/25= ( 3x25+14) / 25 = 89/25
catul = 89 /15
impartitorul = 89/25:89/15=89/25x15/89=3/5
4)[ (6-5)/90·45/1+1/60:(5-4)/60] :3/2=
=[1/90·45/1+1/60·60/1]·2/3=
=(1/2+1)·2/3=3/2·2/3=1
