AE/EB ?
AE /AB =2/5 AE/(AB-AE)=2/(5-2)⇒ AE/EB= 2/3 (Am scazut din numitor numaratorul)
AF/AC ?
AE/AB =AF/AC= 2/5 (EF║BC DIN TEOREMA LUI THALES SEGMENTE PROPORTIONALE)
AF/FC?
AF/AC=2/5 AF/(AC-AF)= 2/(5-2) ⇒ AF/FC=2/3
FC/AC ?
AF/FC=2/3 FC/AF=3/2 FC/(AF+FC)= 2/(3+2) ⇒ FC/AC=2/5 ( Am rasturnat rapoartele si am adunat numaratorul la numitor)
AB/EB?
FC/AC =2/5 AC/FC =5/2 DAR AC/FC=AB/EB =5/2
AC/FC =5/2
