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media aritmetică si geometrica a ne 7-√13 si 7+√13

Răspuns :

[tex]ma= \frac{7- \sqrt{13} + 7+ \sqrt{13}}{2} [/tex]

[tex]ma= \frac{14}{2} [/tex]

[tex]ma=7 [/tex]

[tex]mg = \sqrt{(7 - \sqrt{13} ) (7 + \sqrt{13}) } [/tex]

[tex]mg = \sqrt{ {7}^{2} - { (\sqrt{13}) }^{2} } [/tex]

[tex]mg = \sqrt{49 - 13} [/tex]

[tex]mg = \sqrt{36} [/tex]

[tex]mg = 6[/tex]
Media aritmetică =(a+b)/2=(7-✓13+7+√13)/2=14/2=7
Media geometrica=✓(7-√13)(7+√13)=√(7²-√13²)=√49-13=√36=6