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aflati x:
x+10+2×x+2×x-10+X+15+2×x+35+2×x+20=360


Răspuns :

separam termenii asemenea si respectam ordinea efectuarii operatiilor
x+10+2x+2x-10+x+15+2x+35+2x+20=360
x+2x+2x+x+2x+2x=360-10+10-15-35-20
10x=360-70
10x=290
x=290/10
x=29

= x+2x+2x+x+2x+2x+10-10+15+35+20=360
= 10x+70=360
10x=360-70
10x= 290
X= 290:10
X= 29