M,Al(OH)3= 78g/mol
n(niu)=m/M= 7,8g/78g/mol= 0,1mol
3mol...........1mol
3HCL + Al(OH)3----> AlCl3 +3H2O
x..................0,1mol
x= 0,3molHCl----> m,HCl= nxM= 0,3molX36,5g/mol=...............calculeaza !!!
1mol........1mol
NaOH + Al(OH)3----> Na[Al(OH)4]
x...............0,1mol
x= 0,1mol------->m,NaOH=0,1molx40g/mol=........................calculeaza !!!!!