a+b+c=46
b=a-6⇒a=b+6
b=c-10⇒ c=b+10
Algebric avem:
(b+6)+b+(b+10)=46
3b=46-10-6
3b=30
b=30:3
b=10 (al doilea numar)
a=10+6=16 primul numar
10+10=20 al treilea numar
Verific: 16+10+20=46 (suma numerelor)
Metoda grafica
a l---------l+6
b l---------l } suma lor=46
c l---------l+10
46-6-10=30 suma celor 3 parti egale
30:3=10 (b)
10+6=16(a)
10+10=20 (c)
