a+b+c+d=42
a:b si c sunt numere impare consecutive
a+b+c=d......=> d+d=42...=>2d=42....=>d=42:2....=:d=21
a+b+c=21 => b=a+2 si c=a+4
a+a+2+a+4=21
3a+6=21
3a=21-6
3a=15
a=15:3
a=5
b=5+2
b=7
c=5+4
c=9
5+7+9+21=
=12+30
=42
-----------------------------------------------------
a) |__|
b) |__|+2
c) |__|+4
d) |__|__|__|+2+4
---------------------------
a+a+2+a+4+3a+6=42
6a+12=42
6a=42-12
6a=30
a=30:6
a=5
b=5+2
b=7
c=5+4
c=9
c=5+7+9
c=21
5+7+9+21=42
