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simplificati fractiile:[tex] \frac{ x^{2} +x}{x+1} [/tex]=???? [tex] \frac{ 2 x^{2} -2}{3x+3} [/tex]=????? [tex] \frac{ x^{2} -9}{ x^{2} +6x+9} [/tex]=?????? [tex] \frac{ 4 x^{2} -4x+1}{4 x^{2} -1} [/tex] =?????? UEGENTTTTT!!!!!

Răspuns :

x(x+1)/x+1=x
2(x^2-1)/3(x+1)=[2(x-1)(x+1)]/3(x+1)=2/3×(x-1)
(x-3)(x+3)/(x+3)(x+3)=(x-3)/x+3)
(2x-1)(2x-1)/(2x-1)(2x+1)=2x-1/2x+1
Ai rezolvarea în imagine
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