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Descompuneti E(x)=(x+2)^3-x-2.

Răspuns :

[tex]E(x)=(x+2)^3-x-2\\ E(x)=(x+2)^3-(x+2)\\ E(x)=(x+2)[(x+2)^2-1]\\ E(x)=(x+2)(x+2-1)(x+2+1)\\ E(x)=(x+2)(x+1)(x+3)[/tex]
fie x+2=t
atunci
E(t)=t³-t=t(t²-1)=t(t+1)(t-1) si ne aducem aminte ca t=x+2
deci
E(x)=(x+2)(x+3)(x+1)