1. z=1+i
z²=(1+i)²
z²=1+2i+i²
z²=1+2i-1
z²=2i
2.f(-1)+f(0)+f(1)=(1-2)+(0+0)+(1+2)=2
3. Deoarece bazele sunt egale trebuie sa egalam exponentii:
x²-5x=-3x+3
x²-2x+3=0
(x-3)(x+1)=0 ⇒ x∈{3,-1}
4.Combinari de 6 luate cate 2 = 6!/4! * 2!= 5*6/2=15 submultimi
5.AB=√(3-1)²+(5-5)²
AB=√4 = 2
6.A=AB *AC * sinA/2
A=(12 * 3 * 1/2)/2
A=18/2=9
