fie bc numar
6*bc+5=100a+bcnumar
5*bc numar=100a-5
pt a=1
5*bc=95 ;
bc numar=19
deci abc numar=119
pt a=2
5*bcnumar=195
bcnumar=39
deci abc numar=239
pta=3
5*bcnumar=295
bcnumar=59
deci abc numar=359
pt. a=4
5*bc numar=395
bcnumar=79
abcnumar=479
pt a=5
5*bc numar=495
bc numar=99
abcnumar=599
deci abc ∈{119;239;359;479;599}
