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Calculaţi:
(2x+3y)^2=
(x-10a)^2=
(1/3-2b)^2=

* "^2" - la puterea 2


Răspuns :

(2 x + 3 y) ^2 = 4 x^2 + 12 x y + 9 y^2.


(x - 10 a) ^2 = x^2 - 20 x a + 100 a^2.


(1 / 3 - 2b) ^2 = 1 / 9 - 4b / 3 + 4 b^2.



I hope I helped you :)