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In triunghiul dreptunghic MNP, m(∡M)=90°,MQ⊥NP,Q∈(NP),se dau:
a) PQ=25,6dm si PN=40dm. Calculati NQ si MQ.
b) NQ=9dm si NP=25dm. Calculati QP si MQ.
DAU COROANA!


Răspuns :

a)PQ=25,6 dm
PN=40 dm
NQ=PN-PQ=40-25,6=14,4
MQ²=PQ·QN
MQ²=25,6·14,4=368,64
MQ=√368,64=19,2

B)NQ=9
NP=25
QP=NP-NQ=25-9=16
MQ²=PQ·QN
MQ²=16·9=144
MQ=√144=12