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se dau nunerele a=214 b=2 c=325 sa se afle
a) a×b+c×[(a+b×c)-(a+c)]:5=
b) c+b×a+b×[(c-a)×b-a]=
va rog urgent imi trebuie un raspuns promit ca dau coroana


Răspuns :

a) 214×2+325×[(214+2×325)-(214+325)]:5=

428+325×[(214+650)-539]:5=

428+325×(864-539):5=

428+325×325:5=

428+105 625 : 5=

428+21 125=

21 553

b) 325+2×214+2×[(325-214)×2-214]=

325+428+2×(111×2-214)=

753+2×(222-214)=

753+2×8=

753+16=

769