[tex]\frac{2(x-3)+x+2}{(x+2)*(x+3)} = \frac{2x+6+x+2}{(x+2)*(x+3)} = \frac{3x+8}{x+2*(x+3)} [/tex][/tex]a)
tex] \frac{2(x-3)+x+2}{(x+2)*(x+3)}
= \frac{2x+6+x+2}{(x+2)*(x+3)}
= \frac{3x+8}{x+2*(x+3)} [/tex]
b)
[tex](x+2)* \frac{1}{x+4}
= \frac{x+2}{x+4} [/tex]
c)
[tex] \frac{x-3}{x-4}* \frac{x-5}{x-3}
= \frac{1}{x-4}* (x-5)
= \frac{x-5}{x-4} [/tex]