H3C-C6H5 + 3HONO2 = H3C-C6H2(NO2)3 + 3H2O
n toluen = 460/92 = 5kmoli
nHNO3 = 3n toluen = 15 Kmoli
amestec nitrant : m = 15·63 + 30·98 + ... apa = 3885kg
amestecul nitrant se obtine prin amestecarea solutiilor de HNO3 si H2SO4 , care contin apa
c) teoretic : nTNT = n T = 5kmoli
practic : m TNT = 0,75·5·227 = 851,25 kg