[tex] \frac{(x-2)^2-2(x-2)+1}{x^2-9} * \frac{x+3}{x-3} = \frac{x^2-4x+4-2x+4+1}{(x+3)(x-3)} * \frac{x+3}{x-3} = \frac{x^2-6x+9}{(x+3)(x-3)} * \frac{x+3}{x-3} = \\ \frac{(x-3)^2}{(x+3)(x-3)} * \frac{x+3}{x-3} =[/tex]
se observa ca se simplifica x-3 si x+3 iar dupa mai multe simplificari rezultatul final va fi 1