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Calculați folosind proprietatea a la m : a la n egal cu a la m minus n

Răspuns :

[tex]a^\big{n} = a^\big{m-n} \Rightarrow a^\big{n} = a^\big{m}\cdot a^\big{-n} \Rightarrow a^\big{m} = \dfrac{a^\big{n}}{a^\big{-n}} \Rightarrow a^\big{m} = a^\big{n-(-n)} \Rightarrow \\ \\ \Rightarrow \boxed{a^\big{m} = a^\big{2n}}[/tex]