[tex]\displaystyle Se~da:\\ \\
q=45MJ=45\times 10^6J\\ \\
\eta=50\%=0,5\\ \\
m=120\frac gh=0,002\frac {kg}{min}\\ \\
t=1min\\ \\
\lambda_v=2,25MJ=2,25\times 10^6J\\ \\
m_v=?J\\ \\ \\
Formule:\\ \\
\eta=\frac{Q_u}{Q_t}\\ \\
\eta=\frac{m_v\times\lambda_v}{q\times m\times t}\\ \\
m_v=\frac{\eta\times q\times m\times t}{\lambda_v}\\ \\ \\
Calcule:\\ \\
m_v=\frac{0,5\times 45\times10^6\times 0,002\times 1}{2,25\times 10^6}=0,02kg[/tex]
