n1 moli C6H5-CH3 + Cl2 ⇒H3C-C6H4-Cl (O) + HCl
n2 moli C6H5-CH3 + Cl2 ⇒ H3C-C6H4-Cl (P) + HCl
n3 moli C6H5-CH3 nereactionat
n1/1 = n2/3 = n3/1 = n/5 n1 = n3 = 0,2n n2 = 0,6n
amestec organic final : m = 126,5n1 + 126,5n2 + 92n3 = 25,3n+ 75,9n + 18,4n = 119,6n
% O = 2530/119,6 = 21,15% %P = 7590/119,6 = 63,46%
% T = 1840/119,6 = 15,38%
b) n1 = 25,3/ 126,5 = 0,02 moli n2 = 0,06 moli nCl2 = n1+ n2 = 0,08 moli
V = 0,08·22,4 = 1,792 l