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Consideram punctele A(3,2) B(5,4) C(0,-2) si D(-2,0) Demostrati ca AB=CD

Răspuns :

Folosesti formula AB=[tex] \sqrt{(xB-xA)^2+(yB-yA)^2} [/tex] unde x si y sunt coordonatele celor doua puncte , deci

AB=[tex] \sqrt{(5-2)^2+(4-2)^2)} = \sqrt{8} [/tex]

CD=[tex] \sqrt{(-2-0)^2+(0-(-2))^2} = \sqrt{8} [/tex]
Deci AB=CD