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Daca:a+b+c=198
B-c=123,

atunci:
2a+b+3c=?


Răspuns :

a+b+c=198
b-c=123...=> b=c+123....=>a=(198-123):3

a=(198-123):3
a=75:3
a=25

25+c+123+c=198
2c+148=198
2c=198-148
2c=50
c=50:2
c=25

25+b+25=198
b=198-50
b=148

2a+b+3c=
=25*2+148+25*3
=50+148+75
=198+75
=273

b-c=123
148-25=123