1.fie x traseul de parcurs
prima zi x-3x/7= 7x-3x/7=4x/7.
a doua zi 4x/7 - 3/5din4x/7=8x/35.
3x/7 + 12x/35+32= x
15x+12x+1120=35x
27x+1120=35x
1120=35x-27x
1120=8x
x=1120:8
x= 140km.(lungimea traseului )
b) prima zi = 3·140/7 = 60km.
c) a doua zi = 140-60 = 80km au mai ramas
= 3/5·80 = 48km.
2.
a)Arie patrat = l²
l²=200
l=√200
l patrat=10√2 cm = l dreptunghi
b) Arie dreptunghi = L·l
300=10√2L
L= 300: 10√2
L= 15√2cm.
l= 10√2cm.
c) l gard = 2 (10√2+ 15√2) + 2·10√2
l gard = 50√2+20√2
l gard = 70√2
l gard = ≈ 99m.
