1)Fie cele 3 numere a, x si z
2)x=a+0.83=> a=x- 0,83
3)x=b+0,8(3)=>b=x-0,8(3)
0,8(3)=(83-8)/90=75/90 =15/45= 1/3
Din 1), 2) si 3) => Ma=(a+x+z)/3=>Ma=[x- 0,83 + x + x-0,8(3)]/3=>
=>Ma=(x- 0,83 + x + x-1/3)/3=>
*in paranteza rotunda aduc la acelasi numitor: 300!!!
=>Ma=[(x*300-83*3+x*300+x*300-100)/300]/3=>
=>Ma=[(x*300+x*300+x*300-83*3-100)/300]/3=?
=>Ma=[(3x*300-249-100)/300]/3=>
=>Ma=[(900x-349)/300]/3=>
=>Ma=[(900x-349)/300]*1/3=>
=>Ma=[(900x-349)/300*3=>
=>Ma=[(900x-349)/900=>Ma=900x/900-349/900=>
=>Ma=x-349/900