👤

Aflati numarul x:
2x+14=58
3x+39=90
5x+35=225
(3+x)×8=32
(9+x)÷25=100
(5+7x)×12-28=200
{[(2x+3)×2+3]×2+3=77


Răspuns :

Acesta este răspunsul
Vezi imaginea TIMOTI1
2x+14=58
2x=58-14
2x=44
x=44:2
x=22

3x+39=90
3x=90-39
3x=51
x=51:3
x=17

5x+35=225
5x=225-35
5x=190
x=190:5
x=38

(3+x)•8=32
3+x=32:8
3+x=4
x=4-3
x=1

(9+x):25=100
9+x=25•100
9+x=2500
x=2500-9
x=2491

(5+7x)•12-28=200
(5+7x)•12=200+28
(5+7x)•12=228
5+7x=228:12
5+7x=19
7x=19-5
7x=14
x=14:7
x=2

[(2x+3)•2+3]•2+3=77
[(2x+3)•2+3]•2=77-3
[(2x+3)•2+3]•2=74
(2x+3)•2+3=74:2
(2x+3)•2+3=37
(2x+3)•2=37-3
(2x+3)•2=34
2x+3=34:2
2x+3=17
2x=17-3
2x=14
x=14:2
x=7